What are the solutions to the equation 4m^2+m=5 ?

The solutions to the equation 4m^2+m=5 are m=1,m=-5/4

Find the zeros of 4m^2+m=5

The zeros of 4m^2+m=5 are m=1,m=-5/4

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4 m^{2} + m = 5

m = 1, m = - \frac{5}{4}

Decimal Notation

m = 1, m = - 1.25

Solution steps

4 m^{2} + m = 5

Move

5

to the left side

4 m^{2} + m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 5) = 9

m_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 1 + 9}{2 \cdot 4}, m_{2} = \frac{- 1 - 9}{2 \cdot 4}

m = \frac{- 1 + 9}{2 \cdot 4} : 1

m = \frac{- 1 - 9}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

m = 1, m = - \frac{5}{4}

0 = c^{1} (\frac{1}{2}) + c^{2} (\frac{3}{2})

- 6 y^{2} - 9 y + 1 = 0

8 x^{2} - 22 x + 5 = 0

x, x^{2} + 6 x - 3 = 0

3 x^{2} - 9 x + 4 = 0

What are the solutions to the equation 4m^2+m=5 ?
The solutions to the equation 4m^2+m=5 are m=1,m=-5/4
Find the zeros of 4m^2+m=5
The zeros of 4m^2+m=5 are m=1,m=-5/4