What are the solutions to the equation 4t=2t^2 ?

The solutions to the equation 4t=2t^2 are t=0,t=2

Find the zeros of 4t=2t^2

The zeros of 4t=2t^2 are t=0,t=2

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4 t = 2 t^{2}

t = 0, t = 2

Solution steps

4 t = 2 t^{2}

Move

2 t^{2}

to the left side

4 t - 2 t^{2} = 0

Factor

4 t - 2 t^{2} : - 2 t (t - 2)

- 2 t (t - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or t - 2 = 0

Solve

t - 2 = 0 : t = 2

The solutions to the quadratic equation are:

t = 0, t = 2

\frac{- 9 x ^{2} - 240 x}{80} + 60 = 0

a, (a^{3} b^{5}) (a^{7} b^{5}) = a^{10} b^{10}

2 r^{2} + r - 2 = 0

y, x^{2} + 2 y^{2} = 6

x^{2} = \frac{1}{4} \frac{4 3 + 1}{4}

What are the solutions to the equation 4t=2t^2 ?
The solutions to the equation 4t=2t^2 are t=0,t=2
Find the zeros of 4t=2t^2
The zeros of 4t=2t^2 are t=0,t=2