What are the solutions to the equation x^2+x-34=0 ?

The solutions to the equation x^2+x-34=0 are x=(-1+sqrt(137))/2 ,x=(-1-sqrt(137))/2

Find the zeros of x^2+x-34=0

The zeros of x^2+x-34=0 are x=(-1+sqrt(137))/2 ,x=(-1-sqrt(137))/2

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x^{2} + x - 34 = 0

x = \frac{- 1 + 137}{2}, x = \frac{- 1 - 137}{2}

Decimal Notation

x = 5.35234 \dots, x = - 6.35234 \dots

Solution steps

x^{2} + x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 34 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 34) = 137

x_{1, 2} = \frac{- 1 \pm 137}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 137}{2 \cdot 1}, x_{2} = \frac{- 1 - 137}{2 \cdot 1}

x = \frac{- 1 + 137}{2 \cdot 1} : \frac{- 1 + 137}{2}

x = \frac{- 1 - 137}{2 \cdot 1} : \frac{- 1 - 137}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 137}{2}, x = \frac{- 1 - 137}{2}

m^{2} + 6 m + 1 = 0

t^{2} + 8 t + 1 = 0

- 0.25 x^{2} + 4 x - 9 = x - 2.71

x^{2} - 2 x + 81 = 0

3 x^{2} - 5 x - 1 = 0

What are the solutions to the equation x^2+x-34=0 ?
The solutions to the equation x^2+x-34=0 are x=(-1+sqrt(137))/2 ,x=(-1-sqrt(137))/2
Find the zeros of x^2+x-34=0
The zeros of x^2+x-34=0 are x=(-1+sqrt(137))/2 ,x=(-1-sqrt(137))/2