What are the solutions to the equation -0.01x^2-0.1x+6=4 ?

The solutions to the equation -0.01x^2-0.1x+6=4 are x=-20,x=10

Find the zeros of -0.01x^2-0.1x+6=4

The zeros of -0.01x^2-0.1x+6=4 are x=-20,x=10

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- 0.01 x^{2} - 0.1 x + 6 = 4

x = - 20, x = 10

Solution steps

- 0.01 x^{2} - 0.1 x + 6 = 4

Multiply both sides by

100

- x^{2} - 10 x + 600 = 400

Move

400

to the left side

- x^{2} - 10 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) \cdot 200}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) \cdot 200 = 30

x_{1, 2} = \frac{- ( - 10 ) \pm 30}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 30}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 30}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 30}{2 ( - 1 )} : - 20

x = \frac{- ( - 10 ) - 30}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 20, x = 10

4 x^{2} - 9 = 16

4 x (x + 6) - x^{2} = 5 x^{2}

25 x^{2} - 100 x = 0

7 x^{2} + 41 x - 6 = 0

z, x^{2} + y^{2} + (z - 2)^{2} = 4

What are the solutions to the equation -0.01x^2-0.1x+6=4 ?
The solutions to the equation -0.01x^2-0.1x+6=4 are x=-20,x=10
Find the zeros of -0.01x^2-0.1x+6=4
The zeros of -0.01x^2-0.1x+6=4 are x=-20,x=10