What are the solutions to the equation 4/5 x^2+1=0 ?

The solutions to the equation 4/5 x^2+1=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i

Find the zeros of 4/5 x^2+1=0

The zeros of 4/5 x^2+1=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i

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\frac{4}{5} x^{2} + 1 = 0

x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

\frac{4}{5} x^{2} + 1 = 0

Move

1

to the right side

\frac{4}{5} x^{2} = - 1

Multiply both sides by

5

4 x^{2} = - 5

Divide both sides by

4

x^{2} = - \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{5}{4}, x = - - \frac{5}{4}

- \frac{5}{4} = \frac{5}{2} i

- - \frac{5}{4} = - \frac{5}{2} i

x = \frac{5}{2} i, x = - \frac{5}{2} i

4 x^{2} + 2 x - 1 = 0

49 n^{2} = 9

x^{2} + 6 x = - 7

(5 p - 25) (p - 7) = 1 - p

25 x^{2} - 3 x - 12 = - 18 x - 12

What are the solutions to the equation 4/5 x^2+1=0 ?
The solutions to the equation 4/5 x^2+1=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i
Find the zeros of 4/5 x^2+1=0
The zeros of 4/5 x^2+1=0 are x=(sqrt(5))/2 i,x=-(sqrt(5))/2 i