What are the solutions to the equation 227-0.25x^2=2+2x^2 ?

The solutions to the equation 227-0.25x^2=2+2x^2 are x=10,x=-10

Find the zeros of 227-0.25x^2=2+2x^2

The zeros of 227-0.25x^2=2+2x^2 are x=10,x=-10

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227 - 0.25 x^{2} = 2 + 2 x^{2}

x = 10, x = - 10

Solution steps

227 - 0.25 x^{2} = 2 + 2 x^{2}

Move

227

to the right side

- 0.25 x^{2} = 2 x^{2} - 225

Move

2 x^{2}

to the left side

- 2.25 x^{2} = - 225

Divide both sides by

- 2.25

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

32 x - 4 = 4 x^{2} + 60

- x^{2} + 10 x + 11 = 0

0 = - x^{2} + 4 x + 3

3 x^{2} + 2 x

y^{2} + 3 y - 7 = 0

What are the solutions to the equation 227-0.25x^2=2+2x^2 ?
The solutions to the equation 227-0.25x^2=2+2x^2 are x=10,x=-10
Find the zeros of 227-0.25x^2=2+2x^2
The zeros of 227-0.25x^2=2+2x^2 are x=10,x=-10