What are the solutions to the equation 1-0.4x+0.04x^2=0 ?

The solutions to the equation 1-0.4x+0.04x^2=0 are x=5

Find the zeros of 1-0.4x+0.04x^2=0

The zeros of 1-0.4x+0.04x^2=0 are x=5

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1 - 0.4 x + 0.04 x^{2} = 0

x = 5

Solution steps

1 - 0.4 x + 0.04 x^{2} = 0

Multiply both sides by

100

100 - 40 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 4 \cdot 100}{2 \cdot 4}

(- 40)^{2} - 4 \cdot 4 \cdot 100 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 40 )}{2 \cdot 4}

\frac{- ( - 40 )}{2 \cdot 4} = 5

x = 5

The solution to the quadratic equation is:

x = 5

(x + 3)^{2} + 2 = 0

144 x^{2} = 25

x, y^{2} + 4 x^{2} = 0

a, a^{2} = b^{2} + c^{2} + 2 c n

- 3 x^{2} + 5 x + 9 = 0

What are the solutions to the equation 1-0.4x+0.04x^2=0 ?
The solutions to the equation 1-0.4x+0.04x^2=0 are x=5
Find the zeros of 1-0.4x+0.04x^2=0
The zeros of 1-0.4x+0.04x^2=0 are x=5