What are the solutions to the equation 2x^2+x-45=0 ?

The solutions to the equation 2x^2+x-45=0 are x= 9/2 ,x=-5

Find the zeros of 2x^2+x-45=0

The zeros of 2x^2+x-45=0 are x= 9/2 ,x=-5

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2 x^{2} + x - 45 = 0

x = \frac{9}{2}, x = - 5

Decimal Notation

x = 4.5, x = - 5

Solution steps

2 x^{2} + x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 45 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 45) = 19

x_{1, 2} = \frac{- 1 \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 19}{2 \cdot 2}, x_{2} = \frac{- 1 - 19}{2 \cdot 2}

x = \frac{- 1 + 19}{2 \cdot 2} : \frac{9}{2}

x = \frac{- 1 - 19}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 5

3 x^{2} - 12 x + 7 = 0

0 = x^{2} - x - 8

- 0.5 x^{2} + 8 x - 9.3 = 0

x^{2} + 4 x - 11 = 0

X^{2} - 2 = 0

What are the solutions to the equation 2x^2+x-45=0 ?
The solutions to the equation 2x^2+x-45=0 are x= 9/2 ,x=-5
Find the zeros of 2x^2+x-45=0
The zeros of 2x^2+x-45=0 are x= 9/2 ,x=-5