What are the solutions to the equation 0=x^2-x-8 ?

The solutions to the equation 0=x^2-x-8 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2

Find the zeros of 0=x^2-x-8

The zeros of 0=x^2-x-8 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2

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0 = x^{2} - x - 8

x = \frac{1 + 33}{2}, x = \frac{1 - 33}{2}

Decimal Notation

x = 3.37228 \dots, x = - 2.37228 \dots

Solution steps

0 = x^{2} - x - 8

Switch sides

x^{2} - x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 8) = 33

x_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 33}{2 \cdot 1}

x = \frac{- ( - 1 ) + 33}{2 \cdot 1} : \frac{1 + 33}{2}

x = \frac{- ( - 1 ) - 33}{2 \cdot 1} : \frac{1 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 33}{2}, x = \frac{1 - 33}{2}

- 0.5 x^{2} + 8 x - 9.3 = 0

x^{2} + 4 x - 11 = 0

X^{2} - 2 = 0

3 x^{2} - 2 x - 15 = 0

n (x) = 3 x^{2} - 18 x + 23

What are the solutions to the equation 0=x^2-x-8 ?
The solutions to the equation 0=x^2-x-8 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2
Find the zeros of 0=x^2-x-8
The zeros of 0=x^2-x-8 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2