What are the solutions to the equation x^2-65x+1050=0 ?

The solutions to the equation x^2-65x+1050=0 are x=35,x=30

Find the zeros of x^2-65x+1050=0

The zeros of x^2-65x+1050=0 are x=35,x=30

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x^{2} - 65 x + 1050 = 0

x = 35, x = 30

Solution steps

x^{2} - 65 x + 1050 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 65 ) \pm ( - 65 ) ^{2} - 4 \cdot 1 \cdot 1050}{2 \cdot 1}

(- 65)^{2} - 4 \cdot 1 \cdot 1050 = 5

x_{1, 2} = \frac{- ( - 65 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 65 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 65 ) - 5}{2 \cdot 1}

x = \frac{- ( - 65 ) + 5}{2 \cdot 1} : 35

x = \frac{- ( - 65 ) - 5}{2 \cdot 1} : 30

The solutions to the quadratic equation are:

x = 35, x = 30

6 a^{2} - a - 1 = 0

r, r^{2} - 2 b r + b = 0

(x - 8) (x - 4) = - 4

x, 2 x^{2} + 4 y^{2} + 8 x - 8 y + 12 = 0

(2 x - 1) (6 x + 8) = 4 (x^{2} - 5)

What are the solutions to the equation x^2-65x+1050=0 ?
The solutions to the equation x^2-65x+1050=0 are x=35,x=30
Find the zeros of x^2-65x+1050=0
The zeros of x^2-65x+1050=0 are x=35,x=30