What are the solutions to the equation completesquare 2x^2-7x=0 ?

The solutions to the equation completesquare 2x^2-7x=0 are x= 7/2 ,x=0

Find the zeros of completesquare 2x^2-7x=0

The zeros of completesquare 2x^2-7x=0 are x= 7/2 ,x=0

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2 x^{2} - 7 x = 0

x = \frac{7}{2}, x = 0

Decimal Notation

x = 3.5, x = 0

Solution steps

2 x^{2} - 7 x = 0

Divide both sides by

2

\frac{2 x ^{2} - 7 x}{2} = \frac{0}{2}

x^{2} - \frac{7 x}{2} = 0

Rewrite in the form

(x + a)^{2} = b

(x - \frac{7}{4})^{2} = \frac{49}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{7}{4} = \frac{49}{16} : x = \frac{7}{2}

Solve

x - \frac{7}{4} = - \frac{49}{16} : x = 0

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 0

c, 2 c d - d^{2} = 1 0^{2} + c^{2} - 5^{2}

x^{2} - 765 x + 1 = 0

4 c - 12 = 4 - 4 c + c^{2}

(2 x + 7) (x + 8) = 6 x + 35

2 x (- 2 (- x + 2) + 4) = (x + 2) (x - 2)

What are the solutions to the equation completesquare 2x^2-7x=0 ?
The solutions to the equation completesquare 2x^2-7x=0 are x= 7/2 ,x=0
Find the zeros of completesquare 2x^2-7x=0
The zeros of completesquare 2x^2-7x=0 are x= 7/2 ,x=0