What are the solutions to the equation 12m^2+20m=0 ?

The solutions to the equation 12m^2+20m=0 are m=0,m=-5/3

Find the zeros of 12m^2+20m=0

The zeros of 12m^2+20m=0 are m=0,m=-5/3

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12 m^{2} + 20 m = 0

m = 0, m = - \frac{5}{3}

Decimal Notation

m = 0, m = - 1.66666 \dots

Solution steps

12 m^{2} + 20 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

2 0^{2} - 4 \cdot 12 \cdot 0 = 20

m_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 12}

Separate the solutions

m_{1} = \frac{- 20 + 20}{2 \cdot 12}, m_{2} = \frac{- 20 - 20}{2 \cdot 12}

m = \frac{- 20 + 20}{2 \cdot 12} : 0

m = \frac{- 20 - 20}{2 \cdot 12} : - \frac{5}{3}

The solutions to the quadratic equation are:

m = 0, m = - \frac{5}{3}

- 49 x^{2} + 144 = 0

x, 2 x^{2} - y^{2} = 0

s^{2} + s - 2 + 10 = 0

7 x^{2} - 8 x^{2} - 21 x + 24 = 0

4.5 x^{2} + 32 x = 940

What are the solutions to the equation 12m^2+20m=0 ?
The solutions to the equation 12m^2+20m=0 are m=0,m=-5/3
Find the zeros of 12m^2+20m=0
The zeros of 12m^2+20m=0 are m=0,m=-5/3