What are the solutions to the equation x^2+9x=8 ?

The solutions to the equation x^2+9x=8 are x=(-9+sqrt(113))/2 ,x=(-9-sqrt(113))/2

Find the zeros of x^2+9x=8

The zeros of x^2+9x=8 are x=(-9+sqrt(113))/2 ,x=(-9-sqrt(113))/2

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x^{2} + 9 x = 8

x = \frac{- 9 + 113}{2}, x = \frac{- 9 - 113}{2}

Decimal Notation

x = 0.81507 \dots, x = - 9.81507 \dots

Solution steps

x^{2} + 9 x = 8

Move

8

to the left side

x^{2} + 9 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 8) = 113

x_{1, 2} = \frac{- 9 \pm 113}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 113}{2 \cdot 1}, x_{2} = \frac{- 9 - 113}{2 \cdot 1}

x = \frac{- 9 + 113}{2 \cdot 1} : \frac{- 9 + 113}{2}

x = \frac{- 9 - 113}{2 \cdot 1} : \frac{- 9 - 113}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 113}{2}, x = \frac{- 9 - 113}{2}

11.11 x = 1.1 x^{2}

(x^{2} - x + 3) = 5

x, f (x - 1) = x^{2} + 4 x - 5

x, z = 49 - 4 x^{2} - 4 y^{2}

(p + 4) (p + 4) = 25

What are the solutions to the equation x^2+9x=8 ?
The solutions to the equation x^2+9x=8 are x=(-9+sqrt(113))/2 ,x=(-9-sqrt(113))/2
Find the zeros of x^2+9x=8
The zeros of x^2+9x=8 are x=(-9+sqrt(113))/2 ,x=(-9-sqrt(113))/2