What are the solutions to the equation (p+4)(p+4)=25 ?

The solutions to the equation (p+4)(p+4)=25 are p=1,p=-9

Find the zeros of (p+4)(p+4)=25

The zeros of (p+4)(p+4)=25 are p=1,p=-9

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(p + 4) (p + 4) = 25

p = 1, p = - 9

Solution steps

(p + 4) (p + 4) = 25

Simplify

(p + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p + 4 = 25 : p = 1

Solve

p + 4 = - 25 : p = - 9

The solutions to the quadratic equation are:

p = 1, p = - 9

15 x - 5 x^{2} = 0

y^{2} + y - 8 = 0

x, (z - 4)^{2} = 4 x^{2} + 4 y^{2}

D = \frac{n ( n - 3 )}{2}

x^{2} - 76 x + 1080 = 0

What are the solutions to the equation (p+4)(p+4)=25 ?
The solutions to the equation (p+4)(p+4)=25 are p=1,p=-9
Find the zeros of (p+4)(p+4)=25
The zeros of (p+4)(p+4)=25 are p=1,p=-9