What are the solutions to the equation 12x^2-200x+630=0 ?

The solutions to the equation 12x^2-200x+630=0 are x=(50+sqrt(610))/6 ,x=(50-sqrt(610))/6

Find the zeros of 12x^2-200x+630=0

The zeros of 12x^2-200x+630=0 are x=(50+sqrt(610))/6 ,x=(50-sqrt(610))/6

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12 x^{2} - 200 x + 630 = 0

x = \frac{50 + 610}{6}, x = \frac{50 - 610}{6}

Decimal Notation

x = 12.44969 \dots, x = 4.21697 \dots

Solution steps

12 x^{2} - 200 x + 630 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 12 \cdot 630}{2 \cdot 12}

(- 200)^{2} - 4 \cdot 12 \cdot 630 = 4610

x_{1, 2} = \frac{- ( - 200 ) \pm 4 610}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 4 610}{2 \cdot 12}, x_{2} = \frac{- ( - 200 ) - 4 610}{2 \cdot 12}

x = \frac{- ( - 200 ) + 4 610}{2 \cdot 12} : \frac{50 + 610}{6}

x = \frac{- ( - 200 ) - 4 610}{2 \cdot 12} : \frac{50 - 610}{6}

The solutions to the quadratic equation are:

x = \frac{50 + 610}{6}, x = \frac{50 - 610}{6}

225 = x^{2} + 7 x

0 = 3 X^{2} - 4 X + 5

x, x^{2} - 2 x - 4 = 0

(x + 1) (x - 1) - 3 = 0

3 x^{2} - 8 x + 13 = 0

What are the solutions to the equation 12x^2-200x+630=0 ?
The solutions to the equation 12x^2-200x+630=0 are x=(50+sqrt(610))/6 ,x=(50-sqrt(610))/6
Find the zeros of 12x^2-200x+630=0
The zeros of 12x^2-200x+630=0 are x=(50+sqrt(610))/6 ,x=(50-sqrt(610))/6