What are the solutions to the equation 0=3X^2-4X+5 ?

The solutions to the equation 0=3X^2-4X+5 are X= 2/3+i(sqrt(11))/3 ,X= 2/3-i(sqrt(11))/3

Find the zeros of 0=3X^2-4X+5

The zeros of 0=3X^2-4X+5 are X= 2/3+i(sqrt(11))/3 ,X= 2/3-i(sqrt(11))/3

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0 = 3 X^{2} - 4 X + 5

X = \frac{2}{3} + i \frac{11}{3}, X = \frac{2}{3} - i \frac{11}{3}

Solution steps

0 = 3 X^{2} - 4 X + 5

Switch sides

3 X^{2} - 4 X + 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 5 : 211 i

X_{1, 2} = \frac{- ( - 4 ) \pm 2 11 i}{2 \cdot 3}

Separate the solutions

X_{1} = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3}, X_{2} = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3}

X = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3} : \frac{2}{3} + i \frac{11}{3}

X = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3} : \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

X = \frac{2}{3} + i \frac{11}{3}, X = \frac{2}{3} - i \frac{11}{3}

x, x^{2} - 2 x - 4 = 0

(x + 1) (x - 1) - 3 = 0

3 x^{2} - 8 x + 13 = 0

6 m^{2} + 2 m - 4 = 0

x, x^{2} + p x + q = 0

What are the solutions to the equation 0=3X^2-4X+5 ?
The solutions to the equation 0=3X^2-4X+5 are X= 2/3+i(sqrt(11))/3 ,X= 2/3-i(sqrt(11))/3
Find the zeros of 0=3X^2-4X+5
The zeros of 0=3X^2-4X+5 are X= 2/3+i(sqrt(11))/3 ,X= 2/3-i(sqrt(11))/3