What are the solutions to the equation x^2-x+36=0 ?

The solutions to the equation x^2-x+36=0 are x= 1/2+i(sqrt(143))/2 ,x= 1/2-i(sqrt(143))/2

Find the zeros of x^2-x+36=0

The zeros of x^2-x+36=0 are x= 1/2+i(sqrt(143))/2 ,x= 1/2-i(sqrt(143))/2

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x^{2} - x + 36 = 0

x = \frac{1}{2} + i \frac{143}{2}, x = \frac{1}{2} - i \frac{143}{2}

Solution steps

x^{2} - x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 36 : 143 i

x_{1, 2} = \frac{- ( - 1 ) \pm 143 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 143 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 143 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 143 i}{2 \cdot 1} : \frac{1}{2} + i \frac{143}{2}

x = \frac{- ( - 1 ) - 143 i}{2 \cdot 1} : \frac{1}{2} - i \frac{143}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{143}{2}, x = \frac{1}{2} - i \frac{143}{2}

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What are the solutions to the equation x^2-x+36=0 ?
The solutions to the equation x^2-x+36=0 are x= 1/2+i(sqrt(143))/2 ,x= 1/2-i(sqrt(143))/2
Find the zeros of x^2-x+36=0
The zeros of x^2-x+36=0 are x= 1/2+i(sqrt(143))/2 ,x= 1/2-i(sqrt(143))/2