What are the solutions to the equation -10t^2-12t+9982=0 ?

The solutions to the equation -10t^2-12t+9982=0 are t=-161/5 ,t=31

Find the zeros of -10t^2-12t+9982=0

The zeros of -10t^2-12t+9982=0 are t=-161/5 ,t=31

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- 10 t^{2} - 12 t + 9982 = 0

t = - \frac{161}{5}, t = 31

Decimal Notation

t = - 32.2, t = 31

Solution steps

- 10 t^{2} - 12 t + 9982 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 10 ) \cdot 9982}{2 ( - 10 )}

(- 12)^{2} - 4 (- 10) \cdot 9982 = 632

t_{1, 2} = \frac{- ( - 12 ) \pm 632}{2 ( - 10 )}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 632}{2 ( - 10 )}, t_{2} = \frac{- ( - 12 ) - 632}{2 ( - 10 )}

t = \frac{- ( - 12 ) + 632}{2 ( - 10 )} : - \frac{161}{5}

t = \frac{- ( - 12 ) - 632}{2 ( - 10 )} : 31

The solutions to the quadratic equation are:

t = - \frac{161}{5}, t = 31

- 8.12 x^{2} + 77.11 x - 35 = 0

3 (x - 3)^{2} = 0

(x + 1)^{2} = - 1

2 \cdot x \cdot (- x) = - 1

0 = \frac{1}{2} x^{2} - 3 x - 2

What are the solutions to the equation -10t^2-12t+9982=0 ?
The solutions to the equation -10t^2-12t+9982=0 are t=-161/5 ,t=31
Find the zeros of -10t^2-12t+9982=0
The zeros of -10t^2-12t+9982=0 are t=-161/5 ,t=31