What are the solutions to the equation (x+1)^2=-1 ?

The solutions to the equation (x+1)^2=-1 are x=i-1,x=-i-1

Find the zeros of (x+1)^2=-1

The zeros of (x+1)^2=-1 are x=i-1,x=-i-1

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(x + 1)^{2} = - 1

x = i - 1, x = - i - 1

Solution steps

(x + 1)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 1 : x = i - 1

Solve

x + 1 = - - 1 : x = - i - 1

The solutions to the quadratic equation are:

x = i - 1, x = - i - 1

2 \cdot x \cdot (- x) = - 1

0 = \frac{1}{2} x^{2} - 3 x - 2

5 x^{2} - 16 x - 22 = 3 x^{2} - 17

- 3 x^{2} - 6 x + 2 = 0

(- t)^{2} - 4 \cdot 3 \cdot (- 2) = 1

What are the solutions to the equation (x+1)^2=-1 ?
The solutions to the equation (x+1)^2=-1 are x=i-1,x=-i-1
Find the zeros of (x+1)^2=-1
The zeros of (x+1)^2=-1 are x=i-1,x=-i-1