What are the solutions to the equation a^2+2a-2=0 ?

The solutions to the equation a^2+2a-2=0 are a=-1+sqrt(3),a=-1-sqrt(3)

Find the zeros of a^2+2a-2=0

The zeros of a^2+2a-2=0 are a=-1+sqrt(3),a=-1-sqrt(3)

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a^{2} + 2 a - 2 = 0

a = - 1 + 3, a = - 1 - 3

Decimal Notation

a = 0.73205 \dots, a = - 2.73205 \dots

Solution steps

a^{2} + 2 a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

a_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, a_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

a = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

a = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

a = - 1 + 3, a = - 1 - 3

- \frac{1}{4} x^{2} + 4 x - 6 = 0

5 x^{2} - 15 x - 10 = 20

- 6 x^{2} + 26 x + 20 = 0

2000 + 5 x^{2} - 200 x = 1192.4

x^{2} + 7 x - 800 = 0

What are the solutions to the equation a^2+2a-2=0 ?
The solutions to the equation a^2+2a-2=0 are a=-1+sqrt(3),a=-1-sqrt(3)
Find the zeros of a^2+2a-2=0
The zeros of a^2+2a-2=0 are a=-1+sqrt(3),a=-1-sqrt(3)