What are the solutions to the equation (x^2)/(10)+5=20-x/2 ?

The solutions to the equation (x^2)/(10)+5=20-x/2 are x=10,x=-15

Find the zeros of (x^2)/(10)+5=20-x/2

The zeros of (x^2)/(10)+5=20-x/2 are x=10,x=-15

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\frac{x ^{2}}{10} + 5 = 20 - \frac{x}{2}

x = 10, x = - 15

Solution steps

\frac{x ^{2}}{10} + 5 = 20 - \frac{x}{2}

Find Least Common Multiplier of

10, 2 : 10

Multiply by LCM=

10

\frac{x ^{2}}{10} \cdot 10 + 5 \cdot 10 = 20 \cdot 10 - \frac{x}{2} \cdot 10

Simplify

x^{2} + 50 = 200 - 5 x

Move

5 x

to the left side

x^{2} + 50 + 5 x = 200

Move

200

to the left side

x^{2} + 5 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 150) = 25

x_{1, 2} = \frac{- 5 \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 25}{2 \cdot 1}, x_{2} = \frac{- 5 - 25}{2 \cdot 1}

x = \frac{- 5 + 25}{2 \cdot 1} : 10

x = \frac{- 5 - 25}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 10, x = - 15

- 0.2 x^{2} + 20 = 0

x^{2} - 4 = - 2 x + 4

0.02 - 0.3 x + x^{2} = 0

- 0.00465 x^{2} + 0.09284 x - 0.44621 = 0

x, z = y^{2} - x^{2}

What are the solutions to the equation (x^2)/(10)+5=20-x/2 ?
The solutions to the equation (x^2)/(10)+5=20-x/2 are x=10,x=-15
Find the zeros of (x^2)/(10)+5=20-x/2
The zeros of (x^2)/(10)+5=20-x/2 are x=10,x=-15