What are the solutions to the equation -0.2x^2+20=0 ?

The solutions to the equation -0.2x^2+20=0 are x=10,x=-10

Find the zeros of -0.2x^2+20=0

The zeros of -0.2x^2+20=0 are x=10,x=-10

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- 0.2 x^{2} + 20 = 0

x = 10, x = - 10

Solution steps

- 0.2 x^{2} + 20 = 0

Move

20

to the right side

- 0.2 x^{2} = - 20

Divide both sides by

- 0.2

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x^{2} - 4 = - 2 x + 4

0.02 - 0.3 x + x^{2} = 0

- 0.00465 x^{2} + 0.09284 x - 0.44621 = 0

x, z = y^{2} - x^{2}

s^{2} - s + 4 = 0

What are the solutions to the equation -0.2x^2+20=0 ?
The solutions to the equation -0.2x^2+20=0 are x=10,x=-10
Find the zeros of -0.2x^2+20=0
The zeros of -0.2x^2+20=0 are x=10,x=-10