What are the solutions to the equation s^2-s+4=0 ?

The solutions to the equation s^2-s+4=0 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2

Find the zeros of s^2-s+4=0

The zeros of s^2-s+4=0 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2

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s^{2} - s + 4 = 0

s = \frac{1}{2} + i \frac{15}{2}, s = \frac{1}{2} - i \frac{15}{2}

Solution steps

s^{2} - s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 4 : 15 i

s_{1, 2} = \frac{- ( - 1 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 15 i}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 15 i}{2 \cdot 1}

s = \frac{- ( - 1 ) + 15 i}{2 \cdot 1} : \frac{1}{2} + i \frac{15}{2}

s = \frac{- ( - 1 ) - 15 i}{2 \cdot 1} : \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

s = \frac{1}{2} + i \frac{15}{2}, s = \frac{1}{2} - i \frac{15}{2}

a^{2} + 6 0^{2} = 6 1^{2}

35 x^{2} - 30 x + 3 = 0

6 x^{2} + 6 x + 6 = 0

(x) = - 4 x^{2} - 22 x - 10

2 x^{2} + 12 x - 7 = 0

What are the solutions to the equation s^2-s+4=0 ?
The solutions to the equation s^2-s+4=0 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2
Find the zeros of s^2-s+4=0
The zeros of s^2-s+4=0 are s= 1/2+i(sqrt(15))/2 ,s= 1/2-i(sqrt(15))/2