What are the solutions to the equation (x)=-4x^2-22x-10 ?

The solutions to the equation (x)=-4x^2-22x-10 are x=-(23+3sqrt(41))/8 ,x=-(23-3sqrt(41))/8

Find the zeros of (x)=-4x^2-22x-10

The zeros of (x)=-4x^2-22x-10 are x=-(23+3sqrt(41))/8 ,x=-(23-3sqrt(41))/8

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(x) = - 4 x^{2} - 22 x - 10

x = - \frac{23 + 3 41}{8}, x = - \frac{23 - 3 41}{8}

Decimal Notation

x = - 5.27617 \dots, x = - 0.47382 \dots

Solution steps

(x) = - 4 x^{2} - 22 x - 10

Refine

x = - 4 x^{2} - 22 x - 10

Switch sides

- 4 x^{2} - 22 x - 10 = x

Move

x

to the left side

- 4 x^{2} - 23 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 ( - 4 ) ( - 10 )}{2 ( - 4 )}

(- 23)^{2} - 4 (- 4) (- 10) = 341

x_{1, 2} = \frac{- ( - 23 ) \pm 3 41}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 3 41}{2 ( - 4 )}, x_{2} = \frac{- ( - 23 ) - 3 41}{2 ( - 4 )}

x = \frac{- ( - 23 ) + 3 41}{2 ( - 4 )} : - \frac{23 + 3 41}{8}

x = \frac{- ( - 23 ) - 3 41}{2 ( - 4 )} : - \frac{23 - 3 41}{8}

The solutions to the quadratic equation are:

x = - \frac{23 + 3 41}{8}, x = - \frac{23 - 3 41}{8}

2 x^{2} + 12 x - 7 = 0

c = 200 - 7 x + 0.345 x^{2}

2 x (6 - x) = x (x + 3)

2 x^{2} + 3 x = x

5 c^{2} - 11 c = 12

What are the solutions to the equation (x)=-4x^2-22x-10 ?
The solutions to the equation (x)=-4x^2-22x-10 are x=-(23+3sqrt(41))/8 ,x=-(23-3sqrt(41))/8
Find the zeros of (x)=-4x^2-22x-10
The zeros of (x)=-4x^2-22x-10 are x=-(23+3sqrt(41))/8 ,x=-(23-3sqrt(41))/8