What are the solutions to the equation 2x(6-x)=x(x+3) ?

The solutions to the equation 2x(6-x)=x(x+3) are x=0,x=3

Find the zeros of 2x(6-x)=x(x+3)

The zeros of 2x(6-x)=x(x+3) are x=0,x=3

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2 x (6 - x) = x (x + 3)

x = 0, x = 3

Solution steps

2 x (6 - x) = x (x + 3)

Move

x (x + 3)

to the left side

2 x (6 - x) - x (x + 3) = 0

Factor

2 x (6 - x) - x (x + 3) : - 3 x (x - 3)

- 3 x (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = 0, x = 3

2 x^{2} + 3 x = x

5 c^{2} - 11 c = 12

13 z = - 5 - 6 z^{2}

x^{2} + x^{2} = 9

(x - 5) (2 x + 1) = 0

What are the solutions to the equation 2x(6-x)=x(x+3) ?
The solutions to the equation 2x(6-x)=x(x+3) are x=0,x=3
Find the zeros of 2x(6-x)=x(x+3)
The zeros of 2x(6-x)=x(x+3) are x=0,x=3