What are the solutions to the equation x^2+x^2=9 ?

The solutions to the equation x^2+x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of x^2+x^2=9

The zeros of x^2+x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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x^{2} + x^{2} = 9

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

x^{2} + x^{2} = 9

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 9

Divide both sides by

2

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

(x - 5) (2 x + 1) = 0

128 = \frac{2}{1125} q^{2} + 40

2 x^{1} - 3 x^{2} = - 2, 4 x^{1} - 12 x^{2} = 4

x^{2} + 3 x - 9 = 0

5 x^{2} + 3 = 128

What are the solutions to the equation x^2+x^2=9 ?
The solutions to the equation x^2+x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of x^2+x^2=9
The zeros of x^2+x^2=9 are x= 3/(sqrt(2)),x=-3/(sqrt(2))