What are the solutions to the equation 5x^2+3=128 ?

The solutions to the equation 5x^2+3=128 are x=5,x=-5

Find the zeros of 5x^2+3=128

The zeros of 5x^2+3=128 are x=5,x=-5

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5 x^{2} + 3 = 128

x = 5, x = - 5

Solution steps

5 x^{2} + 3 = 128

Move

3

to the right side

5 x^{2} = 125

Divide both sides by

5

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

p^{2} = 6 p - 4

m^{2} + 3 - 12 m = 0

x^{2} - 2 = 2 + 2 x - x^{2}

k^{2} + 6 k + 9 = 0

x, 5 x^{2} + 6 y^{2} + x y = 34

What are the solutions to the equation 5x^2+3=128 ?
The solutions to the equation 5x^2+3=128 are x=5,x=-5
Find the zeros of 5x^2+3=128
The zeros of 5x^2+3=128 are x=5,x=-5