What are the solutions to the equation k^2+6k+9=0 ?

The solutions to the equation k^2+6k+9=0 are k=-3

Find the zeros of k^2+6k+9=0

The zeros of k^2+6k+9=0 are k=-3

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k^{2} + 6 k + 9 = 0

k = - 3

Solution steps

k^{2} + 6 k + 9 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

k_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

k = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

k = - 3

The solution to the quadratic equation is:

k = - 3

x, 5 x^{2} + 6 y^{2} + x y = 34

x^{2} + (7 - \frac{26}{3})^{2} = 64

2 m^{2} - m^{2} - 18 m + 9 = 0

x^{2} + x + \frac{1}{4} = 0

(x + 3) (2 x - 1) = 9

What are the solutions to the equation k^2+6k+9=0 ?
The solutions to the equation k^2+6k+9=0 are k=-3
Find the zeros of k^2+6k+9=0
The zeros of k^2+6k+9=0 are k=-3