What are the solutions to the equation k^2+6k+8=0 ?

The solutions to the equation k^2+6k+8=0 are k=-2,k=-4

Find the zeros of k^2+6k+8=0

The zeros of k^2+6k+8=0 are k=-2,k=-4

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k^{2} + 6 k + 8 = 0

k = - 2, k = - 4

Solution steps

k^{2} + 6 k + 8 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

k_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 6 + 2}{2 \cdot 1}, k_{2} = \frac{- 6 - 2}{2 \cdot 1}

k = \frac{- 6 + 2}{2 \cdot 1} : - 2

k = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

k = - 2, k = - 4

- 10 x^{2} + 1760 x - 5000 = 0

4 x^{2} = 6 x - 2

- x^{2} + 2 x = 6

5 x^{2} - 16 x + 16 = 0

x^{2} - 9.73 x + 4.5 = 0

What are the solutions to the equation k^2+6k+8=0 ?
The solutions to the equation k^2+6k+8=0 are k=-2,k=-4
Find the zeros of k^2+6k+8=0
The zeros of k^2+6k+8=0 are k=-2,k=-4