What are the solutions to the equation x^2+18x-9=0 ?

The solutions to the equation x^2+18x-9=0 are x=3(sqrt(10)-3),x=-3(3+sqrt(10))

Find the zeros of x^2+18x-9=0

The zeros of x^2+18x-9=0 are x=3(sqrt(10)-3),x=-3(3+sqrt(10))

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x^{2} + 18 x - 9 = 0

x = 3 (10 - 3), x = - 3 (3 + 10)

Decimal Notation

x = 0.48683 \dots, x = - 18.48683 \dots

Solution steps

x^{2} + 18 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 9) = 610

x_{1, 2} = \frac{- 18 \pm 6 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 6 10}{2 \cdot 1}, x_{2} = \frac{- 18 - 6 10}{2 \cdot 1}

x = \frac{- 18 + 6 10}{2 \cdot 1} : 3 (10 - 3)

x = \frac{- 18 - 6 10}{2 \cdot 1} : - 3 (3 + 10)

The solutions to the quadratic equation are:

x = 3 (10 - 3), x = - 3 (3 + 10)

3 x^{2} - 12 x + 5 = 0

(4 k + 5) (k + 7) = 0

x, x^{2} + y^{2} - x + y + 1 = 0

z^{2} - z - 12 = 0

4 x^{2} = - 9 x + 1

What are the solutions to the equation x^2+18x-9=0 ?
The solutions to the equation x^2+18x-9=0 are x=3(sqrt(10)-3),x=-3(3+sqrt(10))
Find the zeros of x^2+18x-9=0
The zeros of x^2+18x-9=0 are x=3(sqrt(10)-3),x=-3(3+sqrt(10))