What are the solutions to the equation (X^1+X^2)=5 ?

The solutions to the equation (X^1+X^2)=5 are X=(-1+sqrt(21))/2 ,X=(-1-sqrt(21))/2

Find the zeros of (X^1+X^2)=5

The zeros of (X^1+X^2)=5 are X=(-1+sqrt(21))/2 ,X=(-1-sqrt(21))/2

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(X^{1} + X^{2}) = 5

X = \frac{- 1 + 21}{2}, X = \frac{- 1 - 21}{2}

Decimal Notation

X = 1.79128 \dots, X = - 2.79128 \dots

Solution steps

(X^{1} + X^{2}) = 5

Refine

X + X^{2} = 5

Move

5

to the left side

X + X^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

X^{2} + X - 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 5) = 21

X_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 1 + 21}{2 \cdot 1}, X_{2} = \frac{- 1 - 21}{2 \cdot 1}

X = \frac{- 1 + 21}{2 \cdot 1} : \frac{- 1 + 21}{2}

X = \frac{- 1 - 21}{2 \cdot 1} : \frac{- 1 - 21}{2}

The solutions to the quadratic equation are:

X = \frac{- 1 + 21}{2}, X = \frac{- 1 - 21}{2}

3 x^{2} - 90 x + 243 = 0

x^{2} - 4 x - 2 = 3

x^{2} = 4 x - 14

24 x^{2} - 28 x + 13 = 0

x^{2} = 55

What are the solutions to the equation (X^1+X^2)=5 ?
The solutions to the equation (X^1+X^2)=5 are X=(-1+sqrt(21))/2 ,X=(-1-sqrt(21))/2
Find the zeros of (X^1+X^2)=5
The zeros of (X^1+X^2)=5 are X=(-1+sqrt(21))/2 ,X=(-1-sqrt(21))/2