What are the solutions to the equation solvefor s,s^2+2s-98=0 ?

The solutions to the equation solvefor s,s^2+2s-98=0 are s=-1+3sqrt(11),s=-1-3sqrt(11)

Find the zeros of solvefor s,s^2+2s-98=0

The zeros of solvefor s,s^2+2s-98=0 are s=-1+3sqrt(11),s=-1-3sqrt(11)

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s, s^{2} + 2 s - 98 = 0

s = - 1 + 311, s = - 1 - 311

Decimal Notation

s = 8.94987 \dots, s = - 10.94987 \dots

Solution steps

s^{2} + 2 s - 98 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 98 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 98) = 611

s_{1, 2} = \frac{- 2 \pm 6 11}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 6 11}{2 \cdot 1}, s_{2} = \frac{- 2 - 6 11}{2 \cdot 1}

s = \frac{- 2 + 6 11}{2 \cdot 1} : - 1 + 311

s = \frac{- 2 - 6 11}{2 \cdot 1} : - 1 - 311

The solutions to the quadratic equation are:

s = - 1 + 311, s = - 1 - 311

0.18 = (1 + \frac{j}{2})^{2} - 1

3 x^{2} - 1 x = 0

- x^{2} + 625 = 0

x, 8 y^{3} = x^{2}

2 x^{2} + 12 x - 182 = 0

What are the solutions to the equation solvefor s,s^2+2s-98=0 ?
The solutions to the equation solvefor s,s^2+2s-98=0 are s=-1+3sqrt(11),s=-1-3sqrt(11)
Find the zeros of solvefor s,s^2+2s-98=0
The zeros of solvefor s,s^2+2s-98=0 are s=-1+3sqrt(11),s=-1-3sqrt(11)