What are the solutions to the equation 4=2x^2+3 ?

The solutions to the equation 4=2x^2+3 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 4=2x^2+3

The zeros of 4=2x^2+3 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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4 = 2 x^{2} + 3

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

4 = 2 x^{2} + 3

Switch sides

2 x^{2} + 3 = 4

Move

3

to the right side

2 x^{2} = 1

Divide both sides by

2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

4.6 y^{2} + 3.5 y - 1.75 = 0

\frac{2}{3} (x - 4) (x + 5) = 1

y, x^{2} y + x^{3} y^{2} = 2

t, d (t) = - 9.81 t^{2} + 10 t m

4 z^{2} - r^{2} = 4

What are the solutions to the equation 4=2x^2+3 ?
The solutions to the equation 4=2x^2+3 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 4=2x^2+3
The zeros of 4=2x^2+3 are x= 1/(sqrt(2)),x=-1/(sqrt(2))