What are the solutions to the equation -x^2+5x+18=0 ?

The solutions to the equation -x^2+5x+18=0 are x=-(-5+sqrt(97))/2 ,x=(5+sqrt(97))/2

Find the zeros of -x^2+5x+18=0

The zeros of -x^2+5x+18=0 are x=-(-5+sqrt(97))/2 ,x=(5+sqrt(97))/2

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- x^{2} + 5 x + 18 = 0

x = - \frac{- 5 + 97}{2}, x = \frac{5 + 97}{2}

Decimal Notation

x = - 2.42442 \dots, x = 7.42442 \dots

Solution steps

- x^{2} + 5 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 18}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 18 = 97

x_{1, 2} = \frac{- 5 \pm 97}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 97}{2 ( - 1 )}, x_{2} = \frac{- 5 - 97}{2 ( - 1 )}

x = \frac{- 5 + 97}{2 ( - 1 )} : - \frac{- 5 + 97}{2}

x = \frac{- 5 - 97}{2 ( - 1 )} : \frac{5 + 97}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 97}{2}, x = \frac{5 + 97}{2}

- 2 (x - 3)^{2} + 8 = 10

v, E = m g h + \frac{m v ^{2}}{2}

18 - x^{2} = 0

m, m^{2} + n^{2} = 10

- 9 x^{2} + 36 x = 38

What are the solutions to the equation -x^2+5x+18=0 ?
The solutions to the equation -x^2+5x+18=0 are x=-(-5+sqrt(97))/2 ,x=(5+sqrt(97))/2
Find the zeros of -x^2+5x+18=0
The zeros of -x^2+5x+18=0 are x=-(-5+sqrt(97))/2 ,x=(5+sqrt(97))/2