What are the solutions to the equation x^2+10x+45=26 ?

The solutions to the equation x^2+10x+45=26 are x=-5+sqrt(6),x=-5-sqrt(6)

Find the zeros of x^2+10x+45=26

The zeros of x^2+10x+45=26 are x=-5+sqrt(6),x=-5-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 10 x + 45 = 26

x = - 5 + 6, x = - 5 - 6

Decimal Notation

x = - 2.55051 \dots, x = - 7.44948 \dots

Solution steps

x^{2} + 10 x + 45 = 26

Move

26

to the left side

x^{2} + 10 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 19 = 26

x_{1, 2} = \frac{- 10 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 6}{2 \cdot 1}

x = \frac{- 10 + 2 6}{2 \cdot 1} : - 5 + 6

x = \frac{- 10 - 2 6}{2 \cdot 1} : - 5 - 6

The solutions to the quadratic equation are:

x = - 5 + 6, x = - 5 - 6

x, x^{2} + 3 x y + y^{3} = 20

5 a^{2} + 4 a = - 2 + 2 a

x, 4 x^{2} - 3 x y - 18 = 0

x^{2} + 3 x + 3 = - 1

y = x^{2} + 3, x

What are the solutions to the equation x^2+10x+45=26 ?
The solutions to the equation x^2+10x+45=26 are x=-5+sqrt(6),x=-5-sqrt(6)
Find the zeros of x^2+10x+45=26
The zeros of x^2+10x+45=26 are x=-5+sqrt(6),x=-5-sqrt(6)