What are the solutions to the equation y^2+18/5 y+81/25 =0 ?

The solutions to the equation y^2+18/5 y+81/25 =0 are y=-9/5

Find the zeros of y^2+18/5 y+81/25 =0

The zeros of y^2+18/5 y+81/25 =0 are y=-9/5

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y^{2} + \frac{18}{5} y + \frac{81}{25} = 0

y = - \frac{9}{5}

Decimal Notation

y = - 1.8

Solution steps

y^{2} + \frac{18}{5} y + \frac{81}{25} = 0

Find Least Common Multiplier of

5, 25 : 25

Multiply by LCM=

25

y^{2} \cdot 25 + \frac{18}{5} y \cdot 25 + \frac{81}{25} \cdot 25 = 0 \cdot 25

Simplify

25 y^{2} + 90 y + 81 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 25 \cdot 81}{2 \cdot 25}

9 0^{2} - 4 \cdot 25 \cdot 81 = 0

y_{1, 2} = \frac{- 90 \pm 0}{2 \cdot 25}

y = \frac{- 90}{2 \cdot 25}

\frac{- 90}{2 \cdot 25} = - \frac{9}{5}

y = - \frac{9}{5}

The solution to the quadratic equation is:

y = - \frac{9}{5}

5 w^{2} + 13 w = - 6

x^{2} + 4 x + 5 = 0

0 + \frac{x ^{2}}{25} = 400

z (3 z + 2) = 8

(x - \frac{1}{6})^{2} - \frac{1}{7} (x + 7) (x - 7) = (x + \frac{1}{6}) - \frac{1}{7} x^{2}

What are the solutions to the equation y^2+18/5 y+81/25 =0 ?
The solutions to the equation y^2+18/5 y+81/25 =0 are y=-9/5
Find the zeros of y^2+18/5 y+81/25 =0
The zeros of y^2+18/5 y+81/25 =0 are y=-9/5