What are the solutions to the equation quadraticformula 2x^2-3x+1=0 ?

The solutions to the equation quadraticformula 2x^2-3x+1=0 are x=1,x= 1/2

Find the zeros of quadraticformula 2x^2-3x+1=0

The zeros of quadraticformula 2x^2-3x+1=0 are x=1,x= 1/2

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2 x^{2} - 3 x + 1 = 0

x = 1, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.5

Solution steps

2 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 2}

x = \frac{- ( - 3 ) + 1}{2 \cdot 2} : 1

x = \frac{- ( - 3 ) - 1}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

\frac{1}{8} x^{2} - \frac{3}{4} x + 1 = 0

0.0102 s^{2} + 0.5151 s + 1.255 = 0

3 x (x - 2) = 8 x^{2} - 7 x

5 x^{2} + 3 x - 14 = - 11 x + 10

x, x^{2} = 3

What are the solutions to the equation quadraticformula 2x^2-3x+1=0 ?
The solutions to the equation quadraticformula 2x^2-3x+1=0 are x=1,x= 1/2
Find the zeros of quadraticformula 2x^2-3x+1=0
The zeros of quadraticformula 2x^2-3x+1=0 are x=1,x= 1/2