What are the solutions to the equation 3x(x-2)=8x^2-7x ?

The solutions to the equation 3x(x-2)=8x^2-7x are x=0,x= 1/5

Find the zeros of 3x(x-2)=8x^2-7x

The zeros of 3x(x-2)=8x^2-7x are x=0,x= 1/5

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3 x (x - 2) = 8 x^{2} - 7 x

x = 0, x = \frac{1}{5}

Decimal Notation

x = 0, x = 0.2

Solution steps

3 x (x - 2) = 8 x^{2} - 7 x

Expand

3 x (x - 2) : 3 x^{2} - 6 x

3 x^{2} - 6 x = 8 x^{2} - 7 x

Move

7 x

to the left side

3 x^{2} + x = 8 x^{2}

Move

8 x^{2}

to the left side

- 5 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

1^{2} - 4 (- 5) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 5 )}, x_{2} = \frac{- 1 - 1}{2 ( - 5 )}

x = \frac{- 1 + 1}{2 ( - 5 )} : 0

x = \frac{- 1 - 1}{2 ( - 5 )} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{5}

5 x^{2} + 3 x - 14 = - 11 x + 10

x, x^{2} = 3

a^{2} - 8 a - 32 = 0

2 x^{2} + 4 = x^{2} + 8

x^{2} + 4 x + 2 = 0

What are the solutions to the equation 3x(x-2)=8x^2-7x ?
The solutions to the equation 3x(x-2)=8x^2-7x are x=0,x= 1/5
Find the zeros of 3x(x-2)=8x^2-7x
The zeros of 3x(x-2)=8x^2-7x are x=0,x= 1/5