What are the solutions to the equation -x^2+17x+30=30 ?

The solutions to the equation -x^2+17x+30=30 are x=0,x=17

Find the zeros of -x^2+17x+30=30

The zeros of -x^2+17x+30=30 are x=0,x=17

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- x^{2} + 17 x + 30 = 30

x = 0, x = 17

Solution steps

- x^{2} + 17 x + 30 = 30

Move

30

to the left side

- x^{2} + 17 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1 7^{2} - 4 (- 1) \cdot 0 = 17

x_{1, 2} = \frac{- 17 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 17 + 17}{2 ( - 1 )}, x_{2} = \frac{- 17 - 17}{2 ( - 1 )}

x = \frac{- 17 + 17}{2 ( - 1 )} : 0

x = \frac{- 17 - 17}{2 ( - 1 )} : 17

The solutions to the quadratic equation are:

x = 0, x = 17

\frac{3 i ^{2} + 3 i}{4 i}

(x + 1) (x - 2) (x + 3) (x + 4)

\frac{( a ^{\frac{5}{3}} )}{y ^{4} x ^{2}}

x^{2} + 4 x = 6

(k^{\frac{3}{2}})^{\frac{1}{2}}

What are the solutions to the equation -x^2+17x+30=30 ?
The solutions to the equation -x^2+17x+30=30 are x=0,x=17
Find the zeros of -x^2+17x+30=30
The zeros of -x^2+17x+30=30 are x=0,x=17