What are the solutions to the equation 4x+8x^2+2=-3x ?

The solutions to the equation 4x+8x^2+2=-3x are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)

Find the zeros of 4x+8x^2+2=-3x

The zeros of 4x+8x^2+2=-3x are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)

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4 x + 8 x^{2} + 2 = - 3 x

x = - \frac{7}{16} + i \frac{15}{16}, x = - \frac{7}{16} - i \frac{15}{16}

Solution steps

4 x + 8 x^{2} + 2 = - 3 x

Move

3 x

to the left side

8 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

Simplify

7^{2} - 4 \cdot 8 \cdot 2 : 15 i

x_{1, 2} = \frac{- 7 \pm 15 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 15 i}{2 \cdot 8}, x_{2} = \frac{- 7 - 15 i}{2 \cdot 8}

x = \frac{- 7 + 15 i}{2 \cdot 8} : - \frac{7}{16} + i \frac{15}{16}

x = \frac{- 7 - 15 i}{2 \cdot 8} : - \frac{7}{16} - i \frac{15}{16}

The solutions to the quadratic equation are:

x = - \frac{7}{16} + i \frac{15}{16}, x = - \frac{7}{16} - i \frac{15}{16}

x, 3 x^{2} + 4 x y + y^{2} = 6

x^{2} - 3 x = 28

31.15 = x^{2} + 4 x + 16

x^{2} - \frac{26}{3} x + 14 = 0

- x^{2} + 5 = - 2

What are the solutions to the equation 4x+8x^2+2=-3x ?
The solutions to the equation 4x+8x^2+2=-3x are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)
Find the zeros of 4x+8x^2+2=-3x
The zeros of 4x+8x^2+2=-3x are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)