What are the solutions to the equation 31.15=x^2+4x+16 ?

The solutions to the equation 31.15=x^2+4x+16 are x=(-20+sqrt(1915))/(10),x=-(20+sqrt(1915))/(10)

Find the zeros of 31.15=x^2+4x+16

The zeros of 31.15=x^2+4x+16 are x=(-20+sqrt(1915))/(10),x=-(20+sqrt(1915))/(10)

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31.15 = x^{2} + 4 x + 16

x = \frac{- 20 + 1915}{10}, x = - \frac{20 + 1915}{10}

Decimal Notation

x = 2.37607 \dots, x = - 6.37607 \dots

Solution steps

31.15 = x^{2} + 4 x + 16

Multiply both sides by

100

3115 = 100 x^{2} + 400 x + 1600

Switch sides

100 x^{2} + 400 x + 1600 = 3115

Move

3115

to the left side

100 x^{2} + 400 x - 1515 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 \cdot 100 ( - 1515 )}{2 \cdot 100}

40 0^{2} - 4 \cdot 100 (- 1515) = 201915

x_{1, 2} = \frac{- 400 \pm 20 1915}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 400 + 20 1915}{2 \cdot 100}, x_{2} = \frac{- 400 - 20 1915}{2 \cdot 100}

x = \frac{- 400 + 20 1915}{2 \cdot 100} : \frac{- 20 + 1915}{10}

x = \frac{- 400 - 20 1915}{2 \cdot 100} : - \frac{20 + 1915}{10}

The solutions to the quadratic equation are:

x = \frac{- 20 + 1915}{10}, x = - \frac{20 + 1915}{10}

x^{2} - \frac{26}{3} x + 14 = 0

- x^{2} + 5 = - 2

X^{2} - 4 X - 5 = 0

- 10 x - x^{2} - 6 = 19

64 - 4 x^{2} = 0

What are the solutions to the equation 31.15=x^2+4x+16 ?
The solutions to the equation 31.15=x^2+4x+16 are x=(-20+sqrt(1915))/(10),x=-(20+sqrt(1915))/(10)
Find the zeros of 31.15=x^2+4x+16
The zeros of 31.15=x^2+4x+16 are x=(-20+sqrt(1915))/(10),x=-(20+sqrt(1915))/(10)