What are the solutions to the equation -10x-x^2-6=19 ?

The solutions to the equation -10x-x^2-6=19 are x=-5

Find the zeros of -10x-x^2-6=19

The zeros of -10x-x^2-6=19 are x=-5

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- 10 x - x^{2} - 6 = 19

x = - 5

Solution steps

- 10 x - x^{2} - 6 = 19

Move

19

to the left side

- x^{2} - 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 10 )}{2 ( - 1 )}

\frac{- ( - 10 )}{2 ( - 1 )} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

64 - 4 x^{2} = 0

x, x y^{2} - 4 x^{2} - 3 y^{2} + 12 x = 0

t^{2} - 5 t + 6 = 0

4 x^{2} - 12 x + 4 = 0

x^{2} - 6 x - 5

What are the solutions to the equation -10x-x^2-6=19 ?
The solutions to the equation -10x-x^2-6=19 are x=-5
Find the zeros of -10x-x^2-6=19
The zeros of -10x-x^2-6=19 are x=-5