What are the solutions to the equation factor 2x^2-5x=3 ?

The solutions to the equation factor 2x^2-5x=3 are x=-1/2 ,x=3

Find the zeros of factor 2x^2-5x=3

The zeros of factor 2x^2-5x=3 are x=-1/2 ,x=3

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2 x^{2} - 5 x = 3

x = - \frac{1}{2}, x = 3

Decimal Notation

x = - 0.5, x = 3

Solution steps

2 x^{2} - 5 x = 3

Move

3

to the left side

2 x^{2} - 5 x - 3 = 0

Factor

2 x^{2} - 5 x - 3 : (2 x + 1) (x - 3)

(2 x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x - 3 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 3

2 x^{2} - 5 x = 0

x^{2} + 2 x + 1 = 3

x^{2} + 4 x + 8 = 0

x^{2} + 2 x + 2 = 9

6 - b^{2} = - 19

What are the solutions to the equation factor 2x^2-5x=3 ?
The solutions to the equation factor 2x^2-5x=3 are x=-1/2 ,x=3
Find the zeros of factor 2x^2-5x=3
The zeros of factor 2x^2-5x=3 are x=-1/2 ,x=3