What are the solutions to the equation x^2+2x+2=9 ?

The solutions to the equation x^2+2x+2=9 are x=-1+2sqrt(2),x=-1-2sqrt(2)

Find the zeros of x^2+2x+2=9

The zeros of x^2+2x+2=9 are x=-1+2sqrt(2),x=-1-2sqrt(2)

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x^{2} + 2 x + 2 = 9

x = - 1 + 22, x = - 1 - 22

Decimal Notation

x = 1.82842 \dots, x = - 3.82842 \dots

Solution steps

x^{2} + 2 x + 2 = 9

Move

9

to the left side

x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 7) = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 2}{2 \cdot 1}

x = \frac{- 2 + 4 2}{2 \cdot 1} : - 1 + 22

x = \frac{- 2 - 4 2}{2 \cdot 1} : - 1 - 22

The solutions to the quadratic equation are:

x = - 1 + 22, x = - 1 - 22

6 - b^{2} = - 19

x, (36 x^{2} - 24 x y + 4 y^{2}) = 69696

25 y^{2} - 9 y = 180

v, E c = \frac{1}{2} m v^{2}

4 a^{2} - 2 a + 3 = 0

What are the solutions to the equation x^2+2x+2=9 ?
The solutions to the equation x^2+2x+2=9 are x=-1+2sqrt(2),x=-1-2sqrt(2)
Find the zeros of x^2+2x+2=9
The zeros of x^2+2x+2=9 are x=-1+2sqrt(2),x=-1-2sqrt(2)