What are the solutions to the equation solvefor x,(36x^2-24xy+4y^2)=69696 ?

The solutions to the equation solvefor x,(36x^2-24xy+4y^2)=69696 are x=(y+132)/3 ,x=(y-132)/3

Find the zeros of solvefor x,(36x^2-24xy+4y^2)=69696

The zeros of solvefor x,(36x^2-24xy+4y^2)=69696 are x=(y+132)/3 ,x=(y-132)/3

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solve for

x, (36 x^{2} - 24 x y + 4 y^{2}) = 69696

x = \frac{y + 132}{3}, x = \frac{y - 132}{3}

Solution steps

(36 x^{2} - 24 x y + 4 y^{2}) = 69696

Refine

36 x^{2} - 24 x y + 4 y^{2} = 69696

Move

69696

to the left side

36 x^{2} - 24 x y + 4 y^{2} - 69696 = 0

Write in the standard form

a x^{2} + b x + c = 0

36 x^{2} - 24 y x + 4 y^{2} - 69696 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 y ) \pm ( - 24 y ) ^{2} - 4 \cdot 36 ( 4 y ^{2} - 69696 )}{2 \cdot 36}

(- 24 y)^{2} - 4 \cdot 36 (4 y^{2} - 69696) = 3168

x_{1, 2} = \frac{- ( - 24 y ) \pm 3168}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 24 y ) + 3168}{2 \cdot 36}, x_{2} = \frac{- ( - 24 y ) - 3168}{2 \cdot 36}

x = \frac{- ( - 24 y ) + 3168}{2 \cdot 36} : \frac{y + 132}{3}

x = \frac{- ( - 24 y ) - 3168}{2 \cdot 36} : \frac{y - 132}{3}

The solutions to the quadratic equation are:

x = \frac{y + 132}{3}, x = \frac{y - 132}{3}

25 y^{2} - 9 y = 180

v, E c = \frac{1}{2} m v^{2}

4 a^{2} - 2 a + 3 = 0

3 = y^{2} + 2 y

\frac{n ( n - 3 )}{2} - n = 25

What are the solutions to the equation solvefor x,(36x^2-24xy+4y^2)=69696 ?
The solutions to the equation solvefor x,(36x^2-24xy+4y^2)=69696 are x=(y+132)/3 ,x=(y-132)/3
Find the zeros of solvefor x,(36x^2-24xy+4y^2)=69696
The zeros of solvefor x,(36x^2-24xy+4y^2)=69696 are x=(y+132)/3 ,x=(y-132)/3