What are the solutions to the equation 25y^2-9y=180 ?

The solutions to the equation 25y^2-9y=180 are y=(9+21sqrt(41))/(50),y=(9-21sqrt(41))/(50)

Find the zeros of 25y^2-9y=180

The zeros of 25y^2-9y=180 are y=(9+21sqrt(41))/(50),y=(9-21sqrt(41))/(50)

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25 y^{2} - 9 y = 180

y = \frac{9 + 21 41}{50}, y = \frac{9 - 21 41}{50}

Decimal Notation

y = 2.86931 \dots, y = - 2.50931 \dots

Solution steps

25 y^{2} - 9 y = 180

Move

180

to the left side

25 y^{2} - 9 y - 180 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 25 ( - 180 )}{2 \cdot 25}

(- 9)^{2} - 4 \cdot 25 (- 180) = 2141

y_{1, 2} = \frac{- ( - 9 ) \pm 21 41}{2 \cdot 25}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 21 41}{2 \cdot 25}, y_{2} = \frac{- ( - 9 ) - 21 41}{2 \cdot 25}

y = \frac{- ( - 9 ) + 21 41}{2 \cdot 25} : \frac{9 + 21 41}{50}

y = \frac{- ( - 9 ) - 21 41}{2 \cdot 25} : \frac{9 - 21 41}{50}

The solutions to the quadratic equation are:

y = \frac{9 + 21 41}{50}, y = \frac{9 - 21 41}{50}

v, E c = \frac{1}{2} m v^{2}

4 a^{2} - 2 a + 3 = 0

3 = y^{2} + 2 y

\frac{n ( n - 3 )}{2} - n = 25

(5 p + 1)^{2} = 12

What are the solutions to the equation 25y^2-9y=180 ?
The solutions to the equation 25y^2-9y=180 are y=(9+21sqrt(41))/(50),y=(9-21sqrt(41))/(50)
Find the zeros of 25y^2-9y=180
The zeros of 25y^2-9y=180 are y=(9+21sqrt(41))/(50),y=(9-21sqrt(41))/(50)