What are the solutions to the equation 5x^2-19x=-12 ?

The solutions to the equation 5x^2-19x=-12 are x=3,x= 4/5

Find the zeros of 5x^2-19x=-12

The zeros of 5x^2-19x=-12 are x=3,x= 4/5

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5 x^{2} - 19 x = - 12

x = 3, x = \frac{4}{5}

Decimal Notation

x = 3, x = 0.8

Solution steps

5 x^{2} - 19 x = - 12

Move

12

to the left side

5 x^{2} - 19 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

(- 19)^{2} - 4 \cdot 5 \cdot 12 = 11

x_{1, 2} = \frac{- ( - 19 ) \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 11}{2 \cdot 5}, x_{2} = \frac{- ( - 19 ) - 11}{2 \cdot 5}

x = \frac{- ( - 19 ) + 11}{2 \cdot 5} : 3

x = \frac{- ( - 19 ) - 11}{2 \cdot 5} : \frac{4}{5}

The solutions to the quadratic equation are:

x = 3, x = \frac{4}{5}

v^{2} + 2 = 16

- 3 x^{2} - 24 x - 45 = 0

5 t^{2} - 3 t - 14 = 0

4 x^{2} + 9 x - 100 = 0

x, 9 x^{2} + 12 x + 4 = 6

What are the solutions to the equation 5x^2-19x=-12 ?
The solutions to the equation 5x^2-19x=-12 are x=3,x= 4/5
Find the zeros of 5x^2-19x=-12
The zeros of 5x^2-19x=-12 are x=3,x= 4/5