What are the solutions to the equation 2^3b^2=2^7 ?

The solutions to the equation 2^3b^2=2^7 are b=4,b=-4

Find the zeros of 2^3b^2=2^7

The zeros of 2^3b^2=2^7 are b=4,b=-4

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2^{3} b^{2} = 2^{7}

b = 4, b = - 4

Solution steps

2^{3} b^{2} = 2^{7}

Divide both sides by

2^{3}

b^{2} = 2^{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 2^{4}, b = - 2^{4}

2^{4} = 4

- 2^{4} = - 4

b = 4, b = - 4

4 x^{2} - 16 x + 16 = 4 x

x^{2} + 6 - 5 x = 0

(x - 1)^{2} - 36 = 0

(x - 1)^{2} - 36 = 1

4 m^{2} + 6 m = 6 m + 36

What are the solutions to the equation 2^3b^2=2^7 ?
The solutions to the equation 2^3b^2=2^7 are b=4,b=-4
Find the zeros of 2^3b^2=2^7
The zeros of 2^3b^2=2^7 are b=4,b=-4