What are the solutions to the equation 7x+x^2-126=0 ?

The solutions to the equation 7x+x^2-126=0 are x=(-7+sqrt(553))/2 ,x=(-7-sqrt(553))/2

Find the zeros of 7x+x^2-126=0

The zeros of 7x+x^2-126=0 are x=(-7+sqrt(553))/2 ,x=(-7-sqrt(553))/2

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7 x + x^{2} - 126 = 0

x = \frac{- 7 + 553}{2}, x = \frac{- 7 - 553}{2}

Decimal Notation

x = 8.25797 \dots, x = - 15.25797 \dots

Solution steps

7 x + x^{2} - 126 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 126 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 126 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 126) = 553

x_{1, 2} = \frac{- 7 \pm 553}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 553}{2 \cdot 1}, x_{2} = \frac{- 7 - 553}{2 \cdot 1}

x = \frac{- 7 + 553}{2 \cdot 1} : \frac{- 7 + 553}{2}

x = \frac{- 7 - 553}{2 \cdot 1} : \frac{- 7 - 553}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 553}{2}, x = \frac{- 7 - 553}{2}

x^{2} + 3 x + 3 + 8 = 0

x, x^{2} + 1 = y^{2} + 1

29.9 - 0.0031 x^{2} = 0

2 (2 x^{2} - 5) = 3 (2 - 3 x^{2}), 4 x^{2} - 3 = 6 - 3 x^{2}

14 = (2 x - 3)^{2} - 2

What are the solutions to the equation 7x+x^2-126=0 ?
The solutions to the equation 7x+x^2-126=0 are x=(-7+sqrt(553))/2 ,x=(-7-sqrt(553))/2
Find the zeros of 7x+x^2-126=0
The zeros of 7x+x^2-126=0 are x=(-7+sqrt(553))/2 ,x=(-7-sqrt(553))/2