What are the solutions to the equation (11-2x)(24-2x)=114 ?

The solutions to the equation (11-2x)(24-2x)=114 are x=15,x= 5/2

Find the zeros of (11-2x)(24-2x)=114

The zeros of (11-2x)(24-2x)=114 are x=15,x= 5/2

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(11 - 2 x) (24 - 2 x) = 114

x = 15, x = \frac{5}{2}

Decimal Notation

x = 15, x = 2.5

Solution steps

(11 - 2 x) (24 - 2 x) = 114

Expand

(11 - 2 x) (24 - 2 x) : 264 - 70 x + 4 x^{2}

264 - 70 x + 4 x^{2} = 114

Move

114

to the left side

4 x^{2} - 70 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 4 \cdot 150}{2 \cdot 4}

(- 70)^{2} - 4 \cdot 4 \cdot 150 = 50

x_{1, 2} = \frac{- ( - 70 ) \pm 50}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 70 ) + 50}{2 \cdot 4}, x_{2} = \frac{- ( - 70 ) - 50}{2 \cdot 4}

x = \frac{- ( - 70 ) + 50}{2 \cdot 4} : 15

x = \frac{- ( - 70 ) - 50}{2 \cdot 4} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 15, x = \frac{5}{2}

\frac{( 15 c ^{2} - 8 c )}{3} = 4

x^{2} = x (4 - x)

5 x^{2} - 8 x + 12 = 3 x + 10

(a + 4)^{2} = 2 a (5 a - 1) - 7 (a - 2)

4 x^{2} - 3 x + c = 0

What are the solutions to the equation (11-2x)(24-2x)=114 ?
The solutions to the equation (11-2x)(24-2x)=114 are x=15,x= 5/2
Find the zeros of (11-2x)(24-2x)=114
The zeros of (11-2x)(24-2x)=114 are x=15,x= 5/2